给定一完全四边形ABCDEF,证明:平面上存在一条直线l和两个点M≠N,满足:
1、若l交AC、AD、CD于U、V、W,则(有向角)∠CMU=∠VMD,∠AMU=∠WMD,∠AMV=∠WMC,M换为N时也成立
2、(有向角)∠CMW=∠EMD,∠BMA=∠AMF且A、M、N、W四点共圆
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1、若l交AC、AD、CD于U、V、W,则(有向角)∠CMU=∠VMD,∠AMU=∠WMD,∠AMV=∠WMC,M换为N时也成立
2、(有向角)∠CMW=∠EMD,∠BMA=∠AMF且A、M、N、W四点共圆
谁家小千金
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