1-35个自然数字里，5个不重复任意数字相加等于*的编程

count = 0
res = []
for x1 in range(1, 32):
for x2 in range(x1+1, 33):
for x3 in range(x2+1, 34):
for x4 in range(x3+1, 35):
for x5 in range(x4+1, 36):
if x1 + x2 + x3 + x4 + x5 == 90:
count += 1
res.append((x1, x2, x3, x4, x5))
print(count) # 输出结果为5910
这个编程我试了一下，好像只适用于等于90，其他的数字，比如91/92/93......好像不咋对