应该可以这样表示:
new num[10]={10,5,9,3,7,4,2,1,8,11};
new i,w=10;
for(i=0;i<3;i++)
{
new ran=random_num(0,9);
if(w!=ran)
{
w=ran;
client_print(id,print_chat,"%d",num[i]);
}
};刚刚给删帖了。为什么发不了源码啊= =。。。。

我是来看直到型法在Pawn里的神气运用的

这个就是能在pawn用的:
new num[10]={10,5,9,3,7,4,2,1,8,11};
new i,w=10;
for(i=0;i<3;i++)
{
new ran=random_num(0,9);
if(w!=ran)
{
w=ran;
client_print(id,print_chat,"%d",num[ran]);
}
else
{
while(ran!=w)
{
ran=random_num(0,9)
}
w=ran
client_print(id,print_chat,"%d",num[ran]);
}
}

new num[10]={10,5,9,3,7,4,2,1,8,11};
new j=9,ran[3]
for(new i=0;i<3;i++)
{
ran[i]=random_num(0,j)
new a=num[ran]
num[ran]=num[j]
num[j]=num[ran]
j--;
}
client_print(id,print_chat,"%d %d %d",ran[0],ran[1],ran[2])

我是来膜拜大神的

楼主说清楚点，你要抽取出来的是什么类型的数据？是单个还是多维数组？

public LuckPlayer(id)
{
new Float:i,player_id[32],num,fornum
get_players(player_id,num,"a")
i=float(num)*get_pcvar_float(g_lucknum)
for(fornum=0;fornum<floatround(i);fornum++)
{
new random_lucker,name[32]
random_lucker=player_id[random_num(1,num)]
get_user_name(random_lucker,name[0],32)
strip_user_weapons(random_lucker)
give_item(random_lucker,"weapon_knife")
give_item(random_lucker,"weapon_deagle")
give_item(random_lucker,"weapon_m249")
client_print(id,print_chat,"[%d]-[%s]是幸运玩家,活着的玩家共有[%d]位",random_lucker,name[0],num)
}@lein神上